Question

Equation of line joining the origin and centroid of a triangle having vertices (1,

-2), (3, 5) and (5, -6).​

Answer 1

Explanation:

the formulae for finding centroid is (x1+x2+x3/3 , y1+y2+y3/3)

so the coordinates of centroid is (1+3+5/3 , -2+5-6/3)

(3,-1) and other point is the origin (0,0)

we know ,the equation is

x-x1/x1-x2= y-y1/y1-y2

x-3/3-0= y-(-1)/-1-0

x-3/3=y+1/-1

-x+3=3y+3

or -x+3y=0

or x-3y=0(multiplying -1 in both sides)

so the eq is x-3y=0 ans

thank u