Question

If h(x)=-(square root) of x-3 (outside square root) plus 5, then what is the value of h(7)?

Answer 1

h(7) = 3

Explanation:

h(x) = -
`√(x-3)` + 5

h(7) = -
`√((7)-3)` + 5

h(7) = -√4 + 5

h(7) = -2 + 5

h(7) = 3