If h(x)=-(square root) of x-3 (outside square root) plus 5, then what is the value of h(7)?

asked Feb 2, 2021 4.4k views

0 votes

7.9k points

Please log in or register to add a comment.

0 votes

Answer:

h(7) = 3

Explanation:

h(x) = -
√(x-3) + 5

h(7) = -
√((7)-3) + 5

h(7) = -√4 + 5

h(7) = -2 + 5

h(7) = 3

7.5k points

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers