If h(x)=-(square root) of x-3 (outside square root) plus 5, then what is the value of h(7)?

asked Feb 2, 2021 4.4k views

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Answer:

h(7) = 3

Explanation:

h(x) = -
√(x-3) + 5

h(7) = -
√((7)-3) + 5

h(7) = -√4 + 5

h(7) = -2 + 5

h(7) = 3

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