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Determine the equation of the exponential function with a common ratio of 2, a horizontal asymptote at y=4, and passing through the point (2,10).

User Dkroy
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8.1k points

1 Answer

2 votes

Answer:


\bold{y=1.5* 2^x+4}

Explanation:

Given:

Exponential function with common ratio 2.

Horizontal asymptote at y = 4

Passes through point (2, 10)

To find:

Equation of the exponential function ?

Solution:

Equation for an exponential function may be given as:


y=ab^x+c

Where b is the common ratio and

c is the y value of horizontal asymptote.


(x, y) are the points on the function.

We are given that:

b = 2

c = 4

Let us put all the given values and find equation.


y=a* 2^x+4

Now, let us put
x = 2, y = 10 to find the value of a.


10=a* 2^2+4\\\Rightarrow a* 2^2=10-4\\\Rightarrow a* 4=6\\\Rightarrow a =1.5


\therefore the equation of exponential function is:


\bold{y=1.5* 2^x+4}

User Douglas Liu
by
8.5k points

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