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I tried different ways of doing the equation but I still didn't get a correct answer ​

I tried different ways of doing the equation but I still didn't get a correct answer-example-1

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6 votes

Answer:


\huge \boxed{\mathrm{0.65 \ in^2}}

Explanation:

Area of square =
s^2


0.5^2 = 0.25

Area of triangle =
(bh)/(2)


(0.5 * 0.4)/(2)=0.1

The surface area of the net = area of square + 4(area of triangle)


0.25+4(0.1)=0.65

User Tzomas
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