Question

The line goes through (-2,3) and (1,-3) find the slope?

Answer 1

m = -2

Step-by-step explanation:

Step 1: Use slope formula to find slope

`m=(y2-y1)/(x2-x1) =(-3-3)/(1-(-2))= (-6)/(3) =-2`

Therefore the slope of the line is -2

Therefore the slope is -2

Answer 2

`\boxed{ \boxed{ \bold {\blue{ - 2}}}}`

Step-by-step explanation:

Let the points be A and B

A ( -2 , 3 ) ⇒( x₁ , y₁ )

B ( 1 , -3 )⇒( x₂ , y₂ )

Now, let's find the slope:

Slope =
`\sf{(y2 - y1)/(x2 - x1) }`

plug the values

⇒
`\sf{ ( - 3 - 3)/(1 - ( - 2)) }`

When there is a ( - ) in front of an expression in parentheses , change the sign of each term in the expression

⇒
`\sf{ ( - 3 - 3)/(1 + 2) }`

Calculate

⇒
`\sf{ ( - 6)/(3) }`

⇒
`\sf{ - 2}`

Hope I helped!

Best regards!!