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2 votes
The line goes through (-2,3) and (1,-3) find the slope?

2 Answers

1 vote

Answer:

m = -2

Step-by-step explanation:

Step 1: Use slope formula to find slope


m=(y2-y1)/(x2-x1) =(-3-3)/(1-(-2))= (-6)/(3) =-2

Therefore the slope of the line is -2

Therefore the slope is -2

User Thierry Dalon
by
8.5k points
3 votes

Answer:


\boxed{ \boxed{ \bold {\blue{ - 2}}}}

Step-by-step explanation:

Let the points be A and B

A ( -2 , 3 ) ⇒( x₁ , y₁ )

B ( 1 , -3 )⇒( x₂ , y₂ )

Now, let's find the slope:

Slope =
\sf{(y2 - y1)/(x2 - x1) }

plug the values


\sf{ ( - 3 - 3)/(1 - ( - 2)) }

When there is a ( - ) in front of an expression in parentheses , change the sign of each term in the expression


\sf{ ( - 3 - 3)/(1 + 2) }

Calculate


\sf{ ( - 6)/(3) }


\sf{ - 2}

Hope I helped!

Best regards!!

User Arsenbonbon
by
7.4k points

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