Question

The area of the indoor sports exhibition is shown below. What is its perimeter? m What is its area? m2

Answer 1

Area = 3097.96
`m^(2)`

Perimeter = 270.96m

Explanation:

Step 1: State the shapes making up the indoor sports exhibiti
`\pi`on

2 rectangles

1 semi circle

Step 2: Find the area and perimeter of the shapes

ARectangle1 = lw = (10)(40) = 400m^2

PRectangel1 = 2l + w = 2(10) + 40 = 60m

ARectangle2 = lw = (33)(68) = 2244m^2

PRectangel2 = l + w = 33 + 68 = 101m

ASemiCicle =
`(\pi r^(2))/(2) =(\pi 17^(2) )/(2) =(289\pi )/(2)=144.5\pi=453.96m^(2)`

PSemiCircle =
`2\pi r=2\pi(17)=35\pi =109.96m`

Step 3: Add up the areas and perimeters

Area = 400 + 2244 + 453.96

Area = 3097.96
`m^(2)`

Perimeter = 60 + 101 + 109.96

Perimeter = 270.96m

Therefore the area of the indoor sports exhibition is 3097.96
`m^(2)` and the perimeter is 270.96 m