Question

Find the perimeter of the quadrant whose radius is 28cm​

Answer 1

`\huge \boxed{\mathrm{99.98 \ cm}}`

Explanation:

A quadrant is quarter of a circle.

The perimeter of a quarter of a circle is
`(2\pi r)/(4) +2r`.

The radius
`r` is 28 cm.

`(2\pi (28))/(4) +2(28)= 99.982297...`

The perimeter of the quadrant with radius 28 cm is approximately 99.98 cm.

Answer 2

`\huge\boxed{Perimeter = 99.98\ cm}`

Explanation:

Quadrant is one - fourth of a circle

Perimeter of quadrant =
`(2\pi r )/(4) + 2r`

Where r = 28 cm

=> P =
`(2(3.14)(28))/(4) + 2(28)`

=> P =
`(3.14)(14) + 56`

=> P =
`43.98 + 56`

=> P = 99.98 cm