Answer:
The formula to find the voltage is:
![v=√(P*R)](https://img.qammunity.org/2021/formulas/mathematics/high-school/2x1w5p7yijyol44nr0za60asqo7pmv66pi.png)
And the voltage is 4 volts
Explanation:
To get the equation of voltage you need to isolate v in one side of the equation. In order to do that, you need to remove the divisor/denominator and its square. How will you do that?
First, multiply both sides with R:
![P*R=(v^(2) )/(R) *R](https://img.qammunity.org/2021/formulas/mathematics/high-school/o6p2zmlvlwkquwhbbbwqdala8v63cki1qd.png)
That would result into removing the divisor R from the right side of the equation:
![P*R=v^(2)](https://img.qammunity.org/2021/formulas/mathematics/high-school/901vldf3fqdlwtuvh04kba7qeje2zfp25m.png)
Next, square-root both sides:
![√(P*R) =\sqrt{v^(2) }](https://img.qammunity.org/2021/formulas/mathematics/high-school/mt6d6wspsk5dpu8qo1rjz8o01d9jrw14em.png)
That would result in removing the square of v from the right side of the equation:
![√(P*R) =v](https://img.qammunity.org/2021/formulas/mathematics/high-school/wofy6gv6qjgdpmh2x8hy5alxx6c1193ime.png)
Thus we get the equation,
.
To find out the voltage, simply replace R with 32 and P with 0.5
![v=√(0.5*32)](https://img.qammunity.org/2021/formulas/mathematics/high-school/x3r6la255yhlllsm0hqt83oez367dnx3h8.png)
![r=√(16)](https://img.qammunity.org/2021/formulas/mathematics/high-school/nu1eaxymi2gm2pdjle2cq4p55eaemh9nfp.png)
![r=4](https://img.qammunity.org/2021/formulas/mathematics/college/n57zc90cjmpd0i8ah2ut2ummpxupl0x2ub.png)
Thus, the voltage is 4 volts.