Hello, please consider the following.
We will multiply the numerator and denominator by
![4+√(6x)](https://img.qammunity.org/2021/formulas/mathematics/college/2xe6lzff8muyfkldf0lbko73uqt6r4wjxb.png)
to get rid of the root in the denominator.
First of all, we cannot divide by 0, right? So, we need to make sure that the denominator is different from 0.
![4-√(6x) =0<=>√(6x)=4\\\\\text{Take the square}\\\\6x=4^2=16\\\\x=(16)/(6)=(8)/(3)](https://img.qammunity.org/2021/formulas/mathematics/college/mzj6xjihnb65f2c43vruimc47klnxs84ki.png)
We need to take any x real number different from 8/3 then and simplify the expression.
Let's do it!
![\begin{aligned}(4)/(4-√(6x))&=(4(4+√(6x)))/((4+√(6x))(4-√(6x)))\\\\&=(4(4+√(6x)))/((4^2-√(6x)^2))\\\\&=(4(4+√(6x)))/((16-6x))\\\\&=(2(4+√(6x)))/((8-3x))\\\\&\large \boxed{=(8+2√(6x))/(8-3x)}\end{aligned}](https://img.qammunity.org/2021/formulas/mathematics/college/aidqosvj1p4fm65p1l042ffmzxwme3mjh6.png)
Thank you