Answer:
Calculated z= 3.515
The Z∝/2 = ±1.96 for ∝= 0.05
The Z∝/2 = ± 2.58 for ∝= 0.01
Yes the company claims valid at a level of significance of 0.05 and 0.01
Explanation:
Here p1= 70% = 0.7
p2= 20/45= 0.444 q= 1-p= 1-.444= 0.56
The level of significance is 0.05 and 0.01
The null and alternative hypotheses are
H0; p1= p2 Ha: p1≠p2
The test statistic used here is
Z= p1-p2/ √pq/n
Z= 0.7-0.44/ √ 0.44*0.56/45
z= 0.26/ √0.2464/45
z= 3.515
The Z∝/2 = ±1.96 for ∝= 0.05
The Z∝/2 = ± 2.58 for ∝= 0.01
For the significance level 0.05 reject null hypothesis
For the significance level 0.01 reject null hypothesis
Yes the company claims valid at a level of significance of 0.05 and 0.01