Question

Find the sum of 1st 50 odd natural numbers

Answer 1

2500

Explanation:

The Sum of First 50 Odd Natural Numbers:

1+3+5+7+9+11+13+15+17+19+21+23+25+27+29+31+33+35+37+39+41+43+45+47+49+51+53+55+57+59+61+63+65+67+69+71+73+75+77+79+81+83+85+87+89+91+93+95+97+99

= 2500

Answer 2

`\Large{ \boxed{ \mathbb{ \pink{SOLUTION:}}}}`

The AP would be like:

• 1, 3, 5, 7........[50 terms]

Now,

➝ First term = 1

➝ Common difference = 2

➝ No. of terms = 50

By using formula,

`\large{ \boxed{ \rm{S_n = (n)/(2) \bigg(2a + (n - 1)d \bigg)}}}`

Here,

• a = First term
• n = number of terms
• d = common difference
• Sn = sum of n terms

Proceeding further,

➝ S50 = 50/2{ 2 × 1 + (50 - 1)2 }

➝ S50 = 25{ 2 + 49 × 2 }

➝ S50 = 25{ 100 }

➝ S50 = 2500

⛈️ Sum of 50 terms of AP = 2500

Shortcut trick:- n^2

Then, Sum of 50(n) terms = 50^2 = 2500

☘️ Hence, solved !!

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