Question

0.25 L of aqueous solution contains 0.025g of HCLO4 (strong acid) what will be the Ph of the solution g

Answer 1

The pH of the solution will be 3

Step-by-step explanation:

The strength of acids is determined by their ability to dissociate into ions in aqueous solution. A strong acid is any compound capable of completely and irreversibly releasing protons or hydrogen ions, H⁺. That is, an acid is said to be strong if it is fully dissociated into hydrogen ions and anions in solution.

Being pH=- log [H⁺] or pH= - log [H₃O⁺] and being a strong acid, all the HClO₃ dissociates:

HClO₄ + H₂O → H₃O⁺ + ClO₄-

So: [HCLO₄]= [H₃O⁺]

The molar concentration is:

`molar concentration=(number of moles of solute)/(volume solution)`

The molar mass of HClO₄ being 100 g / mole, then if 100 grams of the compound are present in 1 mole, 0.025 grams in how many moles are present?

`moles of HClO_(4) =(0.025 grams*1 mole)/(100 grams)`

moles of HClO₄= 0.00025

Then:

`[HClO_(4)]=(0.00025 moles)/(0.25 L)`

`[HClO_(4)]=0.001 ( moles)/( L)`

Being [HCLO₄]= [H₃O⁺]:

pH= - log 0.001

pH= 3

The pH of the solution will be 3