Question

A plane electromagnetic wave travels northward. At one instant, its electric field has a magnitude of 9.6 V/m and points eastward. What are the magnitude (in T) and direction of the magnetic field at this instant?

Answer 1

The values is
`B = 3.2 *10^(-8) \ T`

The direction is out of the plane

Step-by-step explanation:

From the question we are told that

The magnitude of the electric field is
`E = 9.6 \ V/m`

The magnitude of the magnetic field is mathematically represented as

`B = (E)/(c)`

where c is the speed of light with value

`B = ( 9.6)/(3.0 *10^(8))`

`B = 3.2 *10^(-8) \ T`

Given that the direction off the electromagnetic wave( c ) is northward(y-plane ) and the electric field(E) is eastward(x-plane ) then the magnetic field will be acting in the out of the page (z-plane )