Question

How much heat does 25 g of aluminum lose when cooled from 100 ° C to 20 ° C? Express your result in BTU

Answer 1

1.7 BTU

Step-by-step explanation:

q = mCΔT

q = (25 g) (0.9 J/g/°C) (100°C − 20°C)

q = 1800 J

q = 1800 J × (1 BTU / 1055 J)

q = 1.7 BTU