Question

A tent is in the form of a right circular cylinder and cone. The radius of the cone and cylinder is 4 meters. The height of the cylinder and cone are 4.5 meters and 3 meters respectively. Find the outer surface area of the tent. (Assume π = 22 /7)

Answer 1

176m²

Explanation:

When we are asked to find the outer surface area of a geometric shape, it means to find the Lateral or Curved Surface Area of the shape. We are given two shapes above.

Step 1

Find the Outer surface area of the cone

Outer / Lateral surface area of a cone =

πrl

Where l = √r² + h²

r = 4 m

h = 3m

Outer surface area = 22/7 ×√4² + 3²

= 22/7 × √16 + 9

= 22/7 × √25

= 22/7 × 5

= 62.83185m²

Step 2

Find the outer surface area of a cylinder

= 2πrh

π = 22/7

r = 4m

h = 4.5

π = 22/7

Outer surface area of a cylinder = 2 × 22/7 × 4 × 4.5

= 113.09734m²

Step 3

The Outer Surface Area of the Tent = Outer Surface Area of the cone + Outer Surface Area of the cylinder

= 62.83185m² + 113.09734m²

= 175.92919m²

Approximately ≈ 176m²

Therefore, the outer surface area of the tent = 176m²