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What is the equation of the line shown in this graph?

What is the equation of the line shown in this graph?-example-1
User Pavlonator
by
7.9k points

2 Answers

11 votes

Answer:

y = 1

Explanation:

The equation of a line is:


\boxed{ \mathsf{y = mx + c}}

Here,

  • m = slope of the line
  • c = y-intercept
  • y and x are variables

Finding the slope:

The slope of the line is zero, as the line is parallel to the x-axis.

Another way of finding the slope is by calculating the change in y concerning the change in x.

If we take two points that lie on the given line, like:

  • (2,1)
  • (-4,1)


\boxed{slope = (1 - 1)/(2 - ( - 4)) } \\ = 0

So, either way, we get the slope as zero.

=> m = 0

Finding the y-intercept:

The y-intercept of a line is the value of the y coordinate at which the line meets the y-axis, I.e.,

The point that lies on the line with its abscissa(x coordinate) zero.

Here, one such point is:

  • (0, 1)

its y-intercept is 1.

=> c = 1

Finding the equation:

y = mx + c

y = 0 + 1

=> y = 1

That's the equation we've been looking for!

User Leo Odishvili
by
7.6k points
12 votes

Answer:

  • y = 1

Explanation:

The line is parallel to the x-axis and all the points have y- coordinate of 1.

The line is:

  • y = 1
User Arcturus
by
8.1k points

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