Question

PLEASE HELP!! what is the equation of a line that is perpendicular to y = 2x + 4 and passes through the point (4, 6)?

Answer 1

B. y = -
`(1)/(2)`x + 8

Explanation:

The line is perpendicular to line whose equation is:

y = 2x + 4 and;

passes through point (4,6) .

The product slopes of two perpendicular lines is -1.

The slope of the line whose equation is y = 2x + 4 is; 2

Let the slope of the perpendicular line (l2) be
`m_(l2)`

`m_(l2) * 2 = -1`

`m_(l2)` =
`-(1)/(2)`

Taking another point xy on line l2;

`(y - 6)/(x - 4) = -(1)/(2)`

Cross multiplying this gives;

y = -
`(1)/(2)`x + 8 which is the equation of the perpendicular line!

Answer 2

The answer is B)

`y = - (1)/(2)x + 8`