How does one solve for the n+1st term with the nth term of a sequence

Question

asked Sep 25, 2021 144k views

2 Answers

Marko Nikolov · Answer 1 · 2021-09-26T20:27:23+0000

$n^{\text{th}} \text{ term is } 5n+7$

forget n for a while.

let's call it t .

The
$t^{\text{th}} \text{ term is } 5t+7$

agreed? I don't think there should be a problem.

you're asked what's the
$(t+1)^{\text{th}}$ term.

let's call it u . so just like we did before,

$u^{\text{th}} \text{ term is } 5u+7$

but we know,
u=t+1

So,
5u+7=5(t+1)+7=5t+12

does that answer your question?

Brian Rice · Answer 2 · 2021-09-30T15:43:33+0000

Answer:

Explanation:

The nth term of the sequence is

A(n) = 5n + 7

To find the (n+1)st term substitute n+1 into the general equation

That's

For (n + 1)st term

A(n+1) = 5(n+ 1) + 7

A(n+1) = 5n + 5 + 7

Hope this helps you