Question

How does one solve for the n+1st term with the nth term of a sequence

Answer 1

`n^{\text{th}} \text{ term is } 5n+7`

forget n for a while.

let's call it t .

The
`t^{\text{th}} \text{ term is } 5t+7`

agreed? I don't think there should be a problem.

you're asked what's the
`(t+1)^{\text{th}}` term.

let's call it u . so just like we did before,

`u^{\text{th}} \text{ term is } 5u+7`

but we know,
`u=t+1`

So,
`5u+7=5(t+1)+7=5t+12`

does that answer your question?

Answer 2

The answer is option B

Explanation:

The nth term of the sequence is

A(n) = 5n + 7

To find the (n+1)st term substitute n+1 into the general equation

That's

For (n + 1)st term

A(n+1) = 5(n+ 1) + 7

A(n+1) = 5n + 5 + 7

A(n+1) = 5n + 12

Hope this helps you