Question

What is the frequency of a photon having an energy of 4.91 × 10–17 ? (c = 3.00 × 108 m/s, h = 6.63 × 10–34 J · s)​

Answer 1

The frequency of the photon is 7.41*10¹⁶ Hz

Step-by-step explanation:

Planck states that light is made up of photons, whose energy is directly proportional to the frequency of radiation, according to a constant of proportionality, h, which is called Planck's constant. This is expressed by:

E = h*v

where E is the energy, h the Planck constant (whose value is 6.63*10⁻³⁴ J.s) and v the frequency (Hz or s⁻¹).

So the frequency will be:

`v=(E)/(h)`

Being E= 4.91*10⁻¹⁷ J and replacing:

`v=(4.91*10^(-17) J)/(6.63*10^(-34) J.s)`

You can get:

v= 7.41*10¹⁶
`(1)/(s)`= 7.41*10¹⁶ Hz

The frequency of the photon is 7.41*10¹⁶ Hz