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21 votes
21 votes
The two plates of a capacitor hold +2.5 x 10-3 C and

-2.5 x 10-3 C of charge when the potential difference is
950 V. What is the capacitance?

User StephanieF
by
3.0k points

1 Answer

13 votes
13 votes

Answer:

2.63 microfarads

Step-by-step explanation:

C = Q/V = 2.5 x 10^-3 C / 950 V = 2.63 microfarads

User Hubrik
by
3.4k points