Question

If mirror M2 in a Michelson interferometer is moved through 0.233 mm, a shift of 792 bright fringes occurs. What is the wavelength of the light producing the fringe pattern?

Answer 1

The wavelength is
`\lambda = 589 nm`

Step-by-step explanation:

From the question we are told that

The distance of the mirror shift is
`k = 0.233 \ mm = 0.233*10^(-3) \ m`

The number of fringe shift is n = 792

Generally the wavelength producing this fringes is mathematically represented as

`\lambda = ( 2 * k )/( n )`

substituting values

`\lambda = ( 2 * 0.233*10^(-3) )/( 792 )`

`\lambda = 5.885 *10^(-7) \ m`

`\lambda = 589 nm`