Question

A voltaic cell is set up as follows: Anode: Zn electrode in a solution of 0.050 M Zn(NO 3 ) 2 Cathode: Pt electrode with 0.500 atm H 2 (g) in 0.010 M HNO 3 a) Write the overall balanced cell reaction.

Answer 1

`Zn(s) + 2H+(aq)\Rightarrow Zn^(2+)(aq) + H_(2)(g)`

Step-by-step explanation:

Given that,

Anode : Zn electrode in a solution of 0.050 M Zn(NO₃)₂

Cathode : Pt electrode with 0.500 atm H₂(g) in 0.010 M HNO₃

Anode :

`Zn(s)\Rightarrow Zn^(2+)(aq) + 2e^(-)`

Cathode :

`2H+(aq)+2e^(-)\Rightarrow H_(2)(g)`

We need to write the overall balanced cell reaction

Using anode and cathode

`Zn(s) + 2H+(aq)\Rightarrow Zn^(2+)(aq) + H_(2)(g)`

Hence, This is required answer.