Question

The perimeter of a rectangle is 10 feet. If twice the width is equal to half of the length , find the dimensions of this rectangle.

WRITE AS AN EQUATION​

Answer 1

• Answer:

w = 1ft

l = 4ft

• Explanation:

P =2w + 2l

2w = l/2 => l = 4w

10ft = 2w + 2×4w

10ft = 2w + 8w

10ft = 10w

w = 10ft/10

w = 1 ft

l = 4w

l = 4×1ft

l = 4 ft

Answer 2

length = 4 ft

Width = 1 ft

Explanation:

Let length = l ft

Width = w feet

`(1)/(2)l = 2w\\\\l = 2w*2\\\\l = 4w`

Perimeter = 10 ft

2*(l +w)= 10

2*( 4w + w ) = 10

2*5w = 10

10w = 10

Equation: 10w = 10

Divide both sides by 10

10w/10 = 10/10

w = 1 ft

Plug in the value of w in l = 4w

l = 4 *1

l = 4 ft