Question

A chemist prepares a solution of sodium nitrate by measuring out of sodium nitrate into a volumetric flask and filling the flask to the mark with water.

Calculate the concentration in mol/L of the chemist's sodium nitrate solution. Round your answer to 3 significant digits.

Answer 1

5.74M or 5.74 mol/L (to 3 sign. fig.)

Step-by-step explanation:

The molar mass of NaNO3 is 85g/mol, which means that:

1 mole of NaNO3 - 85g

? moles - 122.0g

= 122/85 = 1.44 moles

Concentration in mol/L = no. of moles (moles) ÷ volume (L)

`(1.44)/(0.250)` = 5.74M or 5.74 mol/L (to 3 sign. fig.)

I hope the steps are clear and easy to follow.