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Verify the identity. cot(x - pi/2) = -tan(x)

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Answer:

See below.

Explanation:


\cot(x-(\pi)/(2))=-\tan(x)

Convert the cotangent to cosine over sine:


(\cos(x-(\pi)/(2) ))/(\sin(x-(\pi)/(2))) =-\tan(x)

Use the cofunction identities. The cofunction identities are:


\sin(x)=\cos((\pi)/(2)-x)\\\cos(x)=\sin((\pi)/(2)-x)

To convert this, factor out a negative one from the cosine and sine.


(\cos(-((\pi)/(2)-x )))/(\sin(-((\pi)/(2)-x))) =-\tan(x)

Recall that since cosine is an even function, we can remove the negative. Since sine is an odd function, we can move the negative outside:


(\cos(((\pi)/(2)-x )))/(-\sin(((\pi)/(2)-x))) =-\tan(x)\\-(\sin(x))/(\cos(x)) =-\tan(x)\\-\tan(x)\stackrel{\checkmark}{=}-\tan(x)

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