Answer:
P(t) = {sin7, cos7, 2} + (7cos7, -7sin7, 9)(t-1)
Explanation:
The equation of the tangent line to the given path at the specified value of t is expressed as;
P(t) = f(t0) + f'(t0)(t - t0)
f(t0) = (sin(7t), cos(7t), 2t^9/2)
at t0 = 1;
f(t0) = {sin7(1), cos7(1), 2(1)^9/2}
f(t0) = {sin7, cos7, 2}
f'(t0) = (7cos7t, -7sin7t, 9/2{2t^9/2-1}
f'(t0) = (7cos7t, -7sin7t, 9t^7/2}
If t0 = 1
f'(1) = (7cos7(1), -7sin7(1), 9(1)^7/2)
f'(1) =(7cos7, -7sin7, 9)
Substituting the given function into the tangent equation will give:
P(t) = f(t0) + f'(t0)(t - t0)
P(t)= {sin7, cos7, 2} + (7cos7, -7sin7, 9)(t-1)
The final expression gives the equation of the tangent line to the path.