Answer + Explanation:
For computing the displacement at point B and D we need to determine the following calculations
Pnet = Pc + Pe + Pb
Pnet = 250 + 350 - 50
Pnet = 550 N
Now the deflection for bar AB is
PLab
δab = -------------
ae
550 * 500
= -------------------------
6,000 * 200 x 10³
= 2.292 x 10⁻⁴mm
Now for bar BC it is
PLbc
δbc = ------------
ae
(550 + 50) * 250
= ----------------------
5,000 * 200 x 10³
= 1.5 x 10⁻⁴mm
And for bar CD it is
PLcd
δcd = ------------
ae
(550 - 250 + 50) * 250
= --------------------------------
5,000 * 200 x 10³
= 0.875 x 10⁻⁴mm
Now the displacement is as follows
For B = 2.292 × 10⁻⁴ mm
For D = 4.667 × 10⁻⁴ mm
= 2.292 × 10⁻⁴ + 1.5 × 10⁻⁴ + 0.875 × 10⁻⁴
= 4.667 × 10⁻⁴ mm
We simply applied the above formulas for determining the displacements at points B, D and the same is to be considered