Answer:
A.
The student made an error in step 3 because a is positive in Quadrant IV; therefore,
![cos\theta = (a√(a^2 + b^2))/(a^2 + b^2)](https://img.qammunity.org/2021/formulas/mathematics/college/8yykabbac96yu8s7smzrgn8puawzjnemhi.png)
Explanation:
Given
![P\ (a,b)](https://img.qammunity.org/2021/formulas/mathematics/college/ctqljci5w0vtxk2eiysr8yu1olbv6gwnrc.png)
![r = \± √((a)^2 + (b)^2)](https://img.qammunity.org/2021/formulas/mathematics/college/7jvkughqfoy0oc6uz7p4c7cug7cejjcpx5.png)
![cos\theta = (-a)/(√(a^2 + b^2)) = -(√(a^2 + b^2))/(a^2 + b^2)](https://img.qammunity.org/2021/formulas/mathematics/college/f9gjwdmj08pdp73zay4kclp0nqua1a9yub.png)
Required
Where and which error did the student make
Given that the angle is in the 4th quadrant;
The value of r is positive, a is positive but b is negative;
Hence;
![r = √((a)^2 + (b)^2)](https://img.qammunity.org/2021/formulas/mathematics/college/b8fgcgaei0nh0v32tgb3jyronyebmf8abm.png)
Since a belongs to the x axis and b belongs to the y axis;
is calculated as thus
![cos\theta = (a)/(r)](https://img.qammunity.org/2021/formulas/mathematics/college/se7uzvvg9jaiax8kjm6412wse7uun2i6eh.png)
Substitute
![r = √((a)^2 + (b)^2)](https://img.qammunity.org/2021/formulas/mathematics/college/b8fgcgaei0nh0v32tgb3jyronyebmf8abm.png)
![cos\theta = (a)/(√((a)^2 + (b)^2))](https://img.qammunity.org/2021/formulas/mathematics/college/1uer68lsytnkg7cj7bjgz8of8qaka1uea3.png)
![cos\theta = (a)/(√(a^2 + b^2))](https://img.qammunity.org/2021/formulas/mathematics/college/de0i81sut5bz9tptg48oqm3hbraowfv74r.png)
Rationalize the denominator
![cos\theta = (a)/(√(a^2 + b^2)) * (√(a^2 + b^2))/(√(a^2 + b^2))](https://img.qammunity.org/2021/formulas/mathematics/college/f8jcbekhjtc6xl8xfnbv1wwli63wxpf8vw.png)
![cos\theta = (a√(a^2 + b^2))/(a^2 + b^2)](https://img.qammunity.org/2021/formulas/mathematics/college/8yykabbac96yu8s7smzrgn8puawzjnemhi.png)
So, from the list of given options;
The student's mistake is that a is positive in quadrant iv and his error is in step 3