How to find constant M ? did I do anything wrong here ?

Question

asked Aug 20, 2021 214k views

2 Answers

New Q Open Wid · Answer 1 · 2021-08-24T12:15:37+0000

Answer:

M=-1, N=7

Explanation:

Something went wrong on the 4th line.

From the third line, it should read

2x^2-x+6Mx-3M+4

=x(2x-1+6M) - 3M+4

Equating with the RHS,

2x-1+6M = 2x-7

6M = -7+1 = -6

M = -1

Therefore

N = -3M+4 = -3(-1)+4 = 7

or

M=-1, N=7