Answer:
1. 20 tins of milk
2. Weight of the Carton = 8,4kg ot 8400g
Explanation:
Given
Volume of a Tin = 77cm³
Weight of a tin = 5000g
Volume of Empty Carton = 1540cm³
Weight of Empty Carton = 5000g
Calculating the number of tins of milk
To do this, we have to make use of the given volumes;
And this is done as follows;
![Number = (Volume\ of\ Empty\ Carton)/(Volume\ of\ a\ Tin)](https://img.qammunity.org/2021/formulas/mathematics/high-school/li1j2o1r3r9hoble7lnhfd4vyjlha1c5ph.png)
Substitute 77cm³ for Volume of a Tin and 1540cm³ for Volume of an Empty Carton
![Number = (1540cm^3)/(77cm^3)](https://img.qammunity.org/2021/formulas/mathematics/high-school/yc026itef8luj690bqanj22tehul2pdoma.png)
![Number = 20](https://img.qammunity.org/2021/formulas/mathematics/high-school/a4xgoc7uuyr1f94491nyotyz6aamnxz2bq.png)
Hence, 20 tins of milk will filled the empty carton
Calculating the weight of the Carton after filled with tins of milk
This is calculated as thus;
Total Weight = Weight of Empty Carton + Weight of Tins of Milk
Substitute 5000g for Weight of Empty Carton
Total Weight = 5000g + Weight of Tins of Milk
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Calculating Weight of Tins of Milk
Since 20 tins of milk will fill the empty carton, the
Weight of Tins of Milk = 20 * Weight of 1 Tin of Milk
Weight of Tins of Milk = 20 * 170g
Weight of Tins of Milk = 3400g
_________________________________________
Substitute 3400g for Weight of Tins of Milk
![Total\ Weight = 5000g + 3400g](https://img.qammunity.org/2021/formulas/mathematics/high-school/new1d7amlyed4ec94lhqxqvlmndlo5t4zw.png)
![Total\ Weight = 8400g](https://img.qammunity.org/2021/formulas/mathematics/high-school/usyftf73m2ze7exj7r3wltcp1jyyvmu385.png)
In Kilograms:
![Total\ Weight = 8.4kg](https://img.qammunity.org/2021/formulas/mathematics/high-school/y60ugm651poqjyr27ztzlvr5lwvziqqgkd.png)