Question

Determine the volume occupied by 10 mol of helium at
27 ° C and 82 atm

Answer 1

3.00 L

Step-by-step explanation:

PV = nRT

(82 atm × 101325 Pa/atm) V = (10 mol) (8.314 J/mol/K) (27 + 273) K

V = 0.00300 m³

V = 3.00 L