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Determine the volume occupied by 10 mol of helium at
27 ° C and 82 atm

1 Answer

2 votes

Answer:

3.00 L

Step-by-step explanation:

PV = nRT

(82 atm × 101325 Pa/atm) V = (10 mol) (8.314 J/mol/K) (27 + 273) K

V = 0.00300 m³

V = 3.00 L

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