Question

Simplify each expression using the proper order of operations. please help thank you so much :)


`(41-3^2)/(√(36)*3-26 )`= ?

12 +
`\sqrt[3]{8}` *(9-2)= ?


`(28-(7^2+3))/(-13+3*5)`= ?


`(28)/(4)` -
`\sqrt[3]{8}`*2^3= ?

7^2 - 5* 8+1= ?

(2*
`√(16)`) -(
`\sqrt[3]{27}`*
`√(81)` ) + 7= ?

Answer 1

`\boxed{\mathrm{view \: explanation}}`

Explanation:

Apply order of operations to solve each expression.

`(41-9)/(6 * 3-26)`

`(41-9)/(18-26)`

`(32)/(-8)=-4`

`12+2* 7`

`12+14=26`

`(28-(49+3))/(-13+15)`

`(28-52)/(2)`

`(-24)/(2) =-12`

`7-2 * 8`

`7-16=-9`

`49-40+1`

`=10`

`(2 * 4)-(3 * 9) +7`

`8-27+7`

`=-12`

Answer 2

a)
`\boxed{-4}`

b)
`\boxed{26}`

c)
`\boxed{-12}`

d)
`\boxed{-9}`

e)
`\boxed{10}`

f)
`\boxed{-12}`

Explanation:

1)
`(41 - 3^2)/(√(36)* 3-26 )`

=>
`(41-9)/(6*3-26)`

=>
`(32)/(18-26)`

=>
`(32)/(-8)`

=> -4

2)
`12+\sqrt[3]{8} * (9-2)` ∴
`\sqrt[3]{8} = 2`

=>
`12+2*(7)`

=> 12 + 14

=> 26

3)
`(28-(7^2+3))/(-13+3*5)`

=>
`(28-(49+3))/(-13+15)`

=>
`(28-52)/(2)`

=>
`(-24)/(2)`

=> -12

4)
`(28)/(4) - \sqrt[3]{8} * 2^3`

=> 7 - 2 * 8

=> 7 - 16

=> -9

5)
`7^2-5*8+1`

=> 49 - 40 + 1

=> 9 + 1

=> 10

6)
`(2 * √(16) ) - (\sqrt[3]{27} * √(81) ) + 7`

∴
`√(16) = 4, \sqrt[3]{27} = 3 , √(81) = 9`

=> (2 * 4) - (3 * 9) + 7

=> 8 - 27 + 7

=> -19 + 7

=> -12