This container is composed of a right circular cylinder and a right circular cone. The diameter is 20, the height of the cylinder is 9, and the slant height of the cone is 16. F…

Question

asked Oct 17, 2021 4.6k views

1 Answer

Chipe · Answer 1 · 2021-10-22T11:05:09+0000

Answer:

Explanation:

This problem is on the mensuration of solids, a cylinder and a cone combined (a frustum)

We are required to solve for the total curve surface areas both solids

hence the curve surface area (henceforth CSA) of a cylinder is given as

$CSA-cylinder=2\pi rh$

$CSA-cone= \pi rl$

$Total CSA= 2\pi rh+\pi rl$

Given data

diameter d= 20

radius = d/2= 20/2= 10

height of cylinder h= 9

slant height of cone l= 16

substituting our data into the expression we have

$Total -CSA= 2*\pi *10*9+\pi *10*16\\\\Total -CSA= 565.56+502.72\\\Total -CSA= 1068.28$