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On a coordinate plane, a line is drawn from point J to point K. Point J is at (negative 3, 1) and point K is at (negative 8, 11). What is the y-coordinate of the point that divides the directed line segment from J to K into a ratio of 2:3? y = (StartFraction m Over m + n EndFraction) (y 2 minus y 1) + y 1 –6 –5 5 7

User Moshen
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2 Answers

1 vote

Answer:

5

Explanation:

User Akshat Thakar
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6 votes

Answer: (-5, 5)

Explanation:

J = (-3, 1) K = (-8, 11) ratio 2 : 3 --> 2 + 3 = 5 segments

x-distance from J to K: -8 - (-3) = -5 units

y-distance from J to K: 11 - 1 = 10 units

Divide those distance into 5 segments:

x = -5/5 = -1 unit per segment

y = 10/5 = 2 units per segment

The partition is 2 segments from J:

x = -3 +2(-1) = -5

y = 1 + 2(2) = 5

The partition is located at (-5, 5)

User Stefan Fisk
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