Question

What are the zeros of the quadratic function f(x) = 6x- + 12x-7?

Answer 1

Number 1

Explanation:

Vertex is (−1,−13)

Answer 2

`~~~~~6x^2 +12x -7 =0\\\\\implies x^2 +2x - \frac 76=0\\\\\implies x^2+2x = \frac76\\\\\implies x^2 +2x +1 = \frac 76 +1\\\\\implies (x+1)^2 = \frac{13}6\\\\\implies x+1 = \pm \sqrt{ \frac{13}6}\\\\\implies x = -1 \pm\sqrt{\frac{13} 6}\\\\\text{Hence,}~ x = -1 +\sqrt{\frac{13} 6}~~ \text{and}~~ x = -1-\sqrt{\frac{13} 6}`