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Graph parallelogram ABCD on the graph

below with vertices A(2,0), B(7,0), C(10,3),
D (5,3). What is the area of parallelogram
ABCD?

1 Answer

2 votes

Answer: 25 square units

Explanation:

We mark the points, A(2,0), B(7,0), C(10,3), D (5,3). on a graph and then joined them to make parallelogram ABCD as provided in the attachment.

Area of parallelogram = Base x corresponding height

From the figure, base AB = 7 - 2 units = 5 units

corresponding height: h= 5 units

Now , Area of parallelogram ABCD = base AB x corresponding height

= 5 x 5 square units

= 25 square units

Hence, the area of parallelogram ABCD is 25 square units .

Graph parallelogram ABCD on the graph below with vertices A(2,0), B(7,0), C(10,3), D-example-1