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Austin walks 2/3 of the way to school and stopped to rest. Devyn walks 4/6 of the way to school and stops for a rest. Where are they in their route to school? Who has traveled further?

User Sriramn
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2 Answers

6 votes

Answer:

both are at the same distance

Explanation:

Austin walks 2/3 of the way to school and stopped to rest. Devyn walks 4/6 of the-example-1
User Karthick
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5.1k points
2 votes

Answer:

Austin and Devyn both have 1/3 of the way left on their way to school. They both also have walked the same amount.

Explanation:

If Austin has to walk to his school, which could be said as 3/3 and Austin has already walked 2/3. Then if we conduct the equation 3/3-2/3=x. x=1/3. Now Devyn has already walked 4/6 of the way to school. If she has to walk a total of 6/6, then we can again make an equation 6/6-4/6=2/6. Now if we take the distance that they both have left to their school, its 1/3 and 2/6. These are both equavalent fractions because if you scale up 1/3, it equals to 2/6. Since they both have an equal amount of distance to travel, that must mean that they both have covered the same amount of distance already. We can double check to be sure. 2/3 *2/2=4/6. The reason we used 2/2 is because4/2=2 and 6/3=2.

User Harsukh Makwana
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5.2k points