Question

Find m∠QPR..........

Answer 1

We need to find the value of x.

If R is on the interior of of <QPS, then m<QPR + m<RPS = m<QPS.

Now substitute the measures into the equation.

9x + 16 + 8x + 7 = 40.

Now combine like terms to get 17x + 23 = 40.

Now subtract 23 form both sides to get 17x = 17.

Now divide both sides by 17 to find that x = 1.

Now to find m<QPR which measures 9x + 16°, we can substitute in a 1.

So we have 9(1) + 16 which is 25.

So m<QPR is 25°.

Answer 2

Hey there! :)

Answer:

m∠QPR = 25°.

Explanation:

Given:

m∠QPS = 40°

m∠RPS = 8x + 7°

m∠QPR = 9x + 16°

m∠QPS = m∠RPS + m∠QPR, therefore:

40° = 8x + 7° + 9x + 16°

Combine like terms:

40° = 17x + 23°

Subtract 23° from both sides:

17° = 17x°

Divide both sides by 17:

x = 1°

If m∠QPR = 9x + 16°, substitute in 1 for 'x':

9(1) + 16 = 9 + 16 = 25°.