Question

Solid iron(II) oxide reacts with oxygen gas to produce solid iron(III) oxide. Balance the equation for this reaction (in lowest multiple integers). Write the unbalanced equation for this reaction.

Answer 1

Balance the unbalanced reaction between iron(II) oxide and oxygen gas to produce iron(III) oxide by changing the coefficients to 4 for FeO and 2 for Fe2O3, maintaining the same number of atoms on both sides.

Step-by-step explanation:

The student is asking how to balance the chemical equation where solid iron(II) oxide reacts with oxygen gas to produce solid iron(III) oxide.

The unbalanced chemical equation for this reaction is:

FeO(s) + O2(g) → Fe2O3(s)

To balance the equation, we need to ensure that there is the same number of each type of atom on both sides of the equation. After balancing, the correct equation (in lowest multiple integers) is:

4 FeO(s) + O2(g) → 2 Fe2O3(s)

Answer 2

Hello

I think the reaction is like this FeO+OFe²O³

And the balance reaction is 2Fe+OFe²O³

Step-by-step explanation:

At first we should find sth that has more atoms than the other then for example we realized that we have two atoms of Fe in Fe²O³ then put 2 before FeO and now we have 2 atoms of Fe in right side and 2 atoms of Fe in left then Oxygen in FeO change to 2 atoms of Oxygen and we have an other one in right side that they become 3 atoms of Oxygen and now we have 3 atoms of Oxygen in both right and left side.

Finally our reaction balanced.

Good luck