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if the vertex of a parabola is (-4,6) and another point on the curve is (-3,14), what is the coefficient of the squared expression in the parabola's equation?

User Maets
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1 Answer

7 votes

Answer:

8

Explanation:

The equation of a parabola in vertex form is

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

Here (h, k) = (- 4, 6 ), thus

y = a(x + 4)² + 6

To find a substitute (- 3, 14) into the equation

14 = a(- 3 + 4)² + 6 ( subtract 6 from both sides )

8 = a

Thus the coefficient of the x² term is a = 8

User GrvTyagi
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