Answer:
B. The buoyant force on the copper block is greater than the buoyant force on the lead block.
Step-by-step explanation:
Given;
mass of lead block, m₁ = 200 g = 0.2 kg
mass of copper block, m₂ = 200 g = 0.2 kg
density of water, ρ = 1 g/cm³
density of lead block, ρ₁ = 11.34 g/cm³
density of copper block, ρ₂ = 8.96 g/cm³
The buoyant force on each block is calculated as;
![F_B = mg((density \ of \ fluid)/(density \ of \ object) )](https://img.qammunity.org/2021/formulas/physics/college/wohrndy44yvk7q7lhelgheo752vd2zxy9n.png)
The buoyant force of lead block;
![F_(lead) = 0.2*9.8((1)/(11.34) )\\\\F_(lead) = 0.173 \ N](https://img.qammunity.org/2021/formulas/physics/college/xyrcfbmhl748tphait5n8lwmqowac3pmej.png)
The buoyant force of copper block
![F_(copper) = 0.2*9.8((1)/(8.96))\\\\F_(copper) = 0.219 \ N](https://img.qammunity.org/2021/formulas/physics/college/ie305u59mskqunw4mf2fppnnc4zlu3arbk.png)
Therefore, the buoyant force on the copper block is greater than the buoyant force on the lead block