93.4k views
5 votes
Find the factors of the polynomial 45 x2 - 20 y2​

User Whatswrong
by
8.4k points

2 Answers

4 votes

Answer:

5(3x - 2)(3x + 2)

Explanation:

Please indicate exponentiation with " ^ " : 45 x^2 - 20 y^2​.

Identify the GCF and factor it out: 5(9x^2 - 4y^2)

Recognize that (9x^2 - 4y^2) is the difference of two squares, which factors into (3x - 2y)(3x + 2y)

Then 45 x^2 - 20 y^2 = 5(3x - 2)(3x + 2)

User The Evil Greebo
by
8.6k points
1 vote

Answer:

The factors of the polynomial are 5, ( 3x - 2y), and (3x + 2y)

Explanation:

The given polynomial is 45x² - 20y²

45x² - 20y² = 5 (9x² - 4y²)

45x² - 20y² = 5 [ (3x)² - (2y)² ]

Using difference of two squares, (3x)² - (2y)² = ( 3x - 2y)(3x + 2y)

45x² - 20y² = 5 ( 3x - 2y) (3x + 2y)

The factors of the polynomial are 5, ( 3x - 2y), and (3x + 2y)

User James Nicholson
by
7.8k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories