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Find the factors of the polynomial 45 x2 - 20 y2​

User Whatswrong
by
6.2k points

2 Answers

4 votes

Answer:

5(3x - 2)(3x + 2)

Explanation:

Please indicate exponentiation with " ^ " : 45 x^2 - 20 y^2​.

Identify the GCF and factor it out: 5(9x^2 - 4y^2)

Recognize that (9x^2 - 4y^2) is the difference of two squares, which factors into (3x - 2y)(3x + 2y)

Then 45 x^2 - 20 y^2 = 5(3x - 2)(3x + 2)

User The Evil Greebo
by
6.2k points
1 vote

Answer:

The factors of the polynomial are 5, ( 3x - 2y), and (3x + 2y)

Explanation:

The given polynomial is 45x² - 20y²

45x² - 20y² = 5 (9x² - 4y²)

45x² - 20y² = 5 [ (3x)² - (2y)² ]

Using difference of two squares, (3x)² - (2y)² = ( 3x - 2y)(3x + 2y)

45x² - 20y² = 5 ( 3x - 2y) (3x + 2y)

The factors of the polynomial are 5, ( 3x - 2y), and (3x + 2y)

User James Nicholson
by
5.7k points