122k views
0 votes
With a y-intercept 10, x-intercept 2, and equation of axis of symmetry x-3=0

1 Answer

0 votes

Answer: f(x) = -3x^2 + 3x - 2

Explain: x of vertex:
x =
(-\frac b{2}{a} ) =
-(3)/(-6) = (1)/(2)

y of vertex: y =
f ((1)/(2) ) = - (3)/(4) + (3)/(2) -2=-(5)/(4)

y-intercept: y = -2

x-intercept: y = 0

D = b
^^2 - 4ac = 9 - 24 = - 15 <0. There are no real roots (no x-intercepts) because D<0.

Since a <0, parabola opens downward. The parabola is below the x-axis

User Flerida
by
8.4k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories