Question

With a y-intercept 10, x-intercept 2, and equation of axis of symmetry x-3=0

Answer 1

Answer: f(x) = -3x^2 + 3x - 2

Explain: x of vertex:
`x` =
`(-\frac b{2}{a} )` =
`-(3)/(-6) = (1)/(2)`

y of vertex: y =
`f ((1)/(2) ) = - (3)/(4) + (3)/(2) -2=-(5)/(4)`

y-intercept: y = -2

x-intercept: y = 0

D = b
`^`^2 - 4ac = 9 - 24 = - 15 <0. There are no real roots (no x-intercepts) because D<0.

Since a <0, parabola opens downward. The parabola is below the x-axis