Question

Plsss need help ans this or the before one​

Answer 1

1

Explanation:

Use the form for the factoring of the sum of cubes.

To make this easier to write, we'll use the substitutions ...

a = sin(θ), b = cos(θ)

It looks like you may want to simplify ...

(a³ +b³)/(a +b) +ab

= ((a +b)(a² -ab +b²))/(a +b) +ab

The factors of (a+b) cancel. In this case, we know that a² +b² = 1, so this becomes ...

= (1 -ab) +ab

= 1

`\boxed{\frac{\sin^3{\theta}+\cos^3{\theta}}{sin(\theta)+cos(\theta)}+sin(\theta)cos(\theta)=1}`